The equation is:
$4x^3y^2 = 7x$
Now, we will differentiate both sides with respect to x:
$\frac{d}{dx}(4x^3y^2) = \frac{d}{dx}(7x)$
Using the product rule for differentiation, we get:
$4(3x^2y^2 + x^3\frac{d}{dx}(y^2)) = 7$
Now, we need to find
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