6y^(2/3) + y = z√4
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To do this, we can rewrite y^(2/3) as the cube root of y squared, or y^(2/3) = (y^(1/3))^2. Then, we can substitute this into the expression to get: 6(y^(1/3))^2 + y Simplifying further, we get: 6y^(2/3) + y = z* Now, we need to solve for z. To do this, we can Show more…
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