Q1. Solve the initial value problem: \frac{dy}{dx} = x^2 (1 + y), y(0) = 0. Q2. Solve the linear equation: \frac{dy}{dx} + \frac{1}{x}y = \frac{e^x}{x}.
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To solve the initial value problem 22(1 + y),y(0) = 0, we need to find the function y that satisfies the differential equation 22(1 + y) and the initial condition y(0) = 0. First, we can simplify the differential equation by dividing both sides by 22: 1 + y = Show more…
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