Prove that (cosθ - tanθ)^2 + (sinθ + 1)^2 ≡ 2 + tan^2θ
Added by Scott G.
Step 1
First, we expand the left-hand side of the equation: (cosθ -tanθ )^2+(sinθ +1)^2 = cos^2θ - 2cosθtanθ + tan^2θ + sin^2θ + 2sinθ + 1 = 1 + tan^2θ + 2sinθ - 2cosθtanθ Show more…
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