Prove $P(n): 2^n > n + 4$ for $n \ge 3$
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Step 1
4^(2*3) = 4^6 = 4096 ln(3) + 4 ≈ 1.098 + 4 ≈ 5.098 Since 4096 > 5.098, the base case holds. Now, let's assume that P(k) is true for some arbitrary positive integer k ≥ 3. That is, we assume 4^(2k) > ln(k) + 4. We need to prove that P(k+1) is also true, which Show more…
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