Problem 4 (60 points) Solve the given differential equation.\\ $x^2y'' + 3xy' - 4y = 0$
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The given differential equation is x^2y" + 3xy' + 4y = 0. To rewrite it in standard form, we divide through by x^2: y" + (3/x)y' + (4/x^2)y = 0. Show more…
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