Problem #1: Evaluate the following integral ∫ dx x(ln(9x))
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Then, du/dx = 1/x and v = x. ∫x(In(9x))dx = x^2(In(9x)) - ∫x(1/x)dx Simplifying the second term, we get: ∫x(In(9x))dx = x^2(In(9x)) - ∫dx The integral of dx is just x + C, where C is the constant of integration. ∫x(In(9x))dx = x^2(In(9x)) - x + C Show more…
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