(a) To find the real zeros, we need to set the function equal to zero and solve for $x$:
$$
\frac{1}{2}(2x^2 + 9)^2(x^2 + 7) = 0
$$
Since the first term $(2x^2 + 9)^2$ is squared, it will always be positive, and there are no real zeros that will make this term
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