(1 point) Solve the initial value problem \frac{dy}{dx} + \frac{3y}{x} + 2 = 3x When y(1) = 1 y(x) =
Added by Chad H.
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To do this, we can use separation of variables: dy/dx = (3 - 3y)/2 2dy/(3-3y) = dx Integrating both sides: -2/3 ln|3-3y| = x + C where C is the constant of integration. Solving for y: |3-3y| = e^(-3x/2 - C) If we let A = e^(-C), we can write: |3-3y| = A Show more…
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