point) Solve the following initial value problem: dy + 2y = 8t with X!) = 3
Added by James S.
Close
Step 1
To do this, we can use an integrating factor, which is e^(∫2dx) = e^(2x). Multiplying both sides of the equation by this factor, we get: e^(2x)dy + 2e^(2x)y = 8te^(2x) Now, we can recognize the left-hand side as the product rule of (e^(2x)y), so we can rewrite Show more…
Show all steps
Your feedback will help us improve your experience
Shaiju T and 57 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the following initial value problem: dy / dt + 0.8ty = 6t with y(0) = 1.
Zhumagali S.
Solve the following initial value problem: t(dy/dt) + 9y = 8t with y(1) = 5.
Adi S.
Solve the following initial value problem: dy/dt + 0.6ty = 3t with y(0) = 2
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD