Question

(1 point) Find a non-zero vector $\vec{x}$ perpendicular to the vectors \begin{align} \vec{v} = \begin{bmatrix} -3 \\ -13 \\ -1 \end{bmatrix} \quad \text{and} \quad \vec{u} = \begin{bmatrix} 1 \\ 4 \\ -2 \end{bmatrix} . \end{align}

          (1 point) Find a non-zero vector $\vec{x}$ perpendicular to the vectors \begin{align*} \vec{v} = \begin{bmatrix} -3 \\ -13 \\ -1 \end{bmatrix} \quad \text{and} \quad \vec{u} = \begin{bmatrix} 1 \\ 4 \\ -2 \end{bmatrix} . \end{align*}

(1 point) Find a non-zero vector x⃗ perpendicular to the vectors
v⃗ =
< b m a t r i x >
and u⃗ =
< b m a t r i x >
.

Added by Terri L.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Suman Saurav Thakur

Step 1

First, we need to find the dot product of the two given vectors [ and &. [ . & = (4)(-2) + (-3)(5) + (1)(1) = -8 - 15 + 1 = -22 Show more…

Show all steps

Thanks for your feedback!

point) Find non-zero vector € perpendicular to the vectors [ and & = [4:

Play audio

Feedback

Suman Saurav Thakur and 72 other subject Algebra educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later

Question

(1 point) Find a non-zero vector $\vec{x}$ perpendicular to the vectors \begin{align*} \vec{v} = \begin{bmatrix} -3 \\ -13 \\ -1 \end{bmatrix} \quad \text{and} \quad \vec{u} = \begin{bmatrix} 1 \\ 4 \\ -2 \end{bmatrix} . \end{align*}

Please give Ace some feedback

(1 point) Find a non-zero vector $\vec{x}$ perpendicular to the vectors \begin{align} \vec{v} = \begin{bmatrix} -3 \\ -13 \\ -1 \end{bmatrix} \quad \text{and} \quad \vec{u} = \begin{bmatrix} 1 \\ 4 \\ -2 \end{bmatrix} . \end{align}