2 = (1)/(√(6) - √(5)) + (2)/(√(5) - √(3)) + (1)/(√(6) - 4)

Name: 2 = (1)/(√(6) - √(5)) + (2)/(√(5) - √(3)) + (1)/(√(6) - 4)
Uploaded: 2021-06-02T08:36:25-08:00
Duration: 2 min 10 s
Channel: Goutam Chand
Description: 2 = (1)/(√(6) - √(5)) + (2)/(√(5) - √(3)) + (1)/(√(6) - 4)

Question

Goutam Chand · Accepted Answer

To solve for T6, we need to solve for J3-T. To do this, we use the algebraic identity J3-T=_0L.

Question

2 = \frac{1}{\sqrt{6} - \sqrt{5}} + \frac{2}{\sqrt{5} - \sqrt{3}} + \frac{1}{\sqrt{6} - 4}

Please give Ace some feedback