Question

ABCD is a parallelogram. In the figure, AB = AC, D is the point in the interior of \(\triangle ABC\) such that \(\angle DBC = \angle DCB\). Prove that AD bisects \(\angle BAC\) of \(\triangle ABC\).

          ABCD is a parallelogram.
In the figure, AB = AC, D is the point in the interior of \(\triangle ABC\) such that \(\angle DBC = \angle DCB\). Prove that AD bisects \(\angle BAC\) of \(\triangle ABC\).

ABCD is a parallelogram.
In the figure, AB = AC, D is the point in the interior of ABC such that ∠ DBC = ∠ DCB. Prove that AD bisects ∠ BAC of ABC.

Added by Brandy S.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

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Question

ABCD is a parallelogram. In the figure, AB = AC, D is the point in the interior of \(\triangle ABC\) such that \(\angle DBC = \angle DCB\). Prove that AD bisects \(\angle BAC\) of \(\triangle ABC\).

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