First, we can simplify the square roots:
$$\sqrt{50} = \sqrt{2^1 \cdot 5^1 \cdot 5^1} = 5\sqrt{2}$$
$$\sqrt{125} = \sqrt{5^3} = 5^2\sqrt{5} = 25\sqrt{5}$$
Now, substitute the simplified square roots back into the expression:
$$-2\sqrt{5} - 3(5\sqrt{2}) +
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