Solve the following initial value problem: 4y' = -2, where y(0) = -2.
Added by Cathy S.
Close
Step 1
dy/dx = 4y dy/y = 4dx Integrating both sides, we get: ln|y| = 4x + C where C is the constant of integration. Show more…
Show all steps
Your feedback will help us improve your experience
Syed Mustafa and 79 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve the initial value problem y'' - 4y' + 4y = 0, y(0) = 0, y'(0) = 2
Vanhi N.
Solve the initial value problem for y(t): 4y" + 12y' = -9y, y(0) = -1, y'(0) = 1/2
Gopesh V.
Solve the given initial value problem. y'' - 5y' + 4y = 0; y(0) = 1, y'(0) = -1/2 The solution is y(t) =
Maitreya E.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD