log4(3y^2 - 10) = 2log4(y - 1) + (1)/(2)

Name: log4(3y^2 - 10) = 2log4(y - 1) + (1)/(2)
Uploaded: 2023-07-22T10:28:36-08:00
Duration: 27 s
Channel: Numerade
Description: log4(3y^2 - 10) = 2log4(y - 1) + (1)/(2)

Question

Sahil Kumar · Answer

Now in this problem we need to find out the solution for x, sorry y. We have a log of this is 4

Nick Johnson · Answer

Hello! So given the log equation here where we have log base 4 of 15 minus 2y, and then that&#x27;s g

Ivan Kochetkov · Answer

Hello, here we have to solve the logarithmic equation. So let&#x27;s use the property of logarithm. A

Kathleen Carty · Answer

We have 4 log 4x plus log 42 equal to 3. So the first thing I&#x27;m going to do is use my log proper

Tim Thornhill · Answer

This problem gives us a log equation, and what we want to do first to be able to solve this, sin

Question

\log_4(3y^2 - 10) = 2\log_4(y - 1) + \frac{1}{2}

Please give Ace some feedback