Limits of Function i. $F(x) = 2\sin(\pi x)$; $f'(-3)$
Added by Jennifer K.
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To do this, we can use the chain rule. The derivative of sin(nx) with respect to x is cos(nx) times the derivative of nx with respect to x, which is n. So, the derivative of f(x) = 2sin(nx) is f'(x) = 2ncos(nx). Now, we need to find f'(-3). To do this, we Show more…
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