Question

\lim_{x \to -\infty} \frac{4x^5 + 2x^4 + x^2}{2x^3 + 7x - 6}

          \lim_{x \to -\infty} \frac{4x^5 + 2x^4 + x^2}{2x^3 + 7x - 6}
        
limx →-∞ (4x^5 + 2x^4 + x^2)/(2x^3 + 7x - 6)

Added by Debra C.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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lim_(x->-infty )(4x^(5)+2x^(4)+x^(2))/(2x^(3)+7x-6)
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Transcript

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00:01 Find the length of the curve is y is equals to the given function is y is equals to 3x power 3 upon 2 and x is equals to 0 2 x equals to 5 upon 9 so the length is equals to l is equals to limit equation a to b root 1 plus dy upon dx of whole square dx so y is equals to 3x power 3 upon 2 so dy upon dx is equals to 3 multiplying by 3 upon 2 x power 3 upon 2 minus 1 is equals to 9 upon 2 x power 1 upon 2 so root 1 plus dy upon dy upon dx whole square is equals to root is equals to root 1 plus 9 upon 2 x 1 upon 2 whole square is equals to root 1 plus 81 x upon 4 is equals to root 4 plus 81 x upon 2 so l is equals to l is equals to 1 upon 2 integration 0 to 5 upon 9 root 4 plus 81 x we take 1 upon 2 as a common in this equation so 1 upon 2 integration 0 to 5 9 root 4 plus 81 x so let u is equals to 4 plus 81 x so du is equals to 81 x dx so dx is equals to 1 upon 81 du and the limits are x is equals to 0 for u is…
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