Let x ∈ R. Then, prove that x^2 + |x - 6| > 5.
Added by Holly L.
Step 1
So, the inequality becomes: x^2 + (x - 6) > 5 Now, we can simplify and rearrange the inequality: x^2 + x - 6 - 5 > 0 x^2 + x - 11 > 0 Let's analyze the quadratic expression x^2 + x - 11. It has roots at x = -4.27 and x = 2.27 (approximately). Since the Show more…
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