Question

\begin{bmatrix} x' \\ y' \\ z' \end{bmatrix} = \begin{bmatrix} -k \\ k-y \\ k+y \end{bmatrix} = \begin{bmatrix} -1 & 0 & 0 \\ 1 & -1 & 0 \\ 1 & 1 & 0 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = Ax

          \begin{bmatrix} x' \\ y' \\ z' \end{bmatrix} = \begin{bmatrix} -k \\ k-y \\ k+y \end{bmatrix} = \begin{bmatrix} -1 & 0 & 0 \\ 1 & -1 & 0 \\ 1 & 1 & 0 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = Ax

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=
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< b m a t r i x >

< b m a t r i x >
= Ax

Added by Brett P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Jason Horton

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