Question

INSTRUCTION: Provide the Java code as your analysis and solution of the following problems. 1. Input a number value for LEFT, RIGHT and X. If LEFT is greater than RIGHT, display the first ten numbers in descending order starting from X. If RIGHT is greater than LEFT display the first ten numbers in ascending order starting from X. If RIGHT and LEFT are equal, display "Equal Value" Use the UML diagram below as a guide. The following methods are as follows. testA: CountMe X, RIGHT, LEFT CountMe -X: int + setValues(int,int,int): int + displayCount(int): void setValues (int, int, int) - accepts the value for X, LEFT and RIGHT as parameters and returns the following: 0 if LEFT and RIGHT are equal 1 if LEFT is greater than RIGHT 2 if RIGHT is greater than LEFT. displayCount (int) - accepts the integer that represents the status of RIGHT and LEFT, and then display the expected result.

          INSTRUCTION: Provide the Java code as your analysis and solution of the following problems.
1. Input a number value for LEFT, RIGHT and X. If LEFT is greater than RIGHT, display the first ten numbers in
descending order starting from X. If RIGHT is greater than LEFT display the first ten numbers in ascending
order starting from X. If RIGHT and LEFT are equal, display "Equal Value" Use the UML diagram below as a
guide. The following methods are as follows.
testA: CountMe
X, RIGHT, LEFT
CountMe
-X: int
+ setValues(int,int,int): int
+ displayCount(int): void
setValues (int, int, int) - accepts the value for X, LEFT and RIGHT as parameters and returns
the following:
0 if LEFT and RIGHT are equal
1 if LEFT is greater than RIGHT
2 if RIGHT is greater than LEFT.
displayCount (int) - accepts the integer that represents the status of RIGHT and LEFT, and then
display the expected result.

INSTRUCTION: Provide the Java code as your analysis and solution of the following problems.
1. Input a number value for LEFT, RIGHT and X. If LEFT is greater than RIGHT, display the first ten numbers in
descending order starting from X. If RIGHT is greater than LEFT display the first ten numbers in ascending
order starting from X. If RIGHT and LEFT are equal, display "Equal Value" Use the UML diagram below as a
guide. The following methods are as follows.
testA: CountMe
X, RIGHT, LEFT
CountMe
-X: int
+ setValues(int,int,int): int
+ displayCount(int): void
setValues (int, int, int) - accepts the value for X, LEFT and RIGHT as parameters and returns
the following:
0 if LEFT and RIGHT are equal
1 if LEFT is greater than RIGHT
2 if RIGHT is greater than LEFT.
displayCount (int) - accepts the integer that represents the status of RIGHT and LEFT, and then
display the expected result.

Added by Ann M.

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