3. $\int \frac{(6x^2 - 4)}{(4x^3 - 8x)} dx$
Added by Samuel H.
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Simplify the expression inside the brackets: (6x^2 - 4) / (4x^2 + 8x) = 2(3x^2 - 2) / 4x(x + 2) = (3x^2 - 2) / 2x(x + 2) Show more…
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