Is there a real number $x$ such that $x=\log x ?$ Decide by displaying graphically the system $$ \left\{\begin{array}{l} y=x \\ y=\log x \end{array}\right. $$
Added by Juan S.
Step 1
imgur.com/5JZJZJL.png) We can see that the two graphs intersect at a point with coordinates $(1,1)$. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Hemraj Kumawat and 97 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Systems of Equations and Inequatities
Systems of Equations
Is there a real number $x$ such that $x=\log x ?$ Decide by displaying graphically the system $$\left\{\begin{array}{l}y=x \\y=\log x\end{array}\right.$$
Is there a real number $x$ such that $x=2^{-x} ?$ Decide by displaying graphically the system $$\left\{\begin{array}{l}y=x \\y=2^{-x}\end{array}\right.$$
Recommended Textbooks
Precalculus with Limits
Precalculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD