Question

6. If $y = \frac{\ln x}{x}$, then $\frac{dy}{dx} = $\\ (A) $\frac{1}{x}$ (B) $\frac{1}{x^2}$ (C) $\frac{\ln x - 1}{x^2}$ (D) $\frac{1 - \ln x}{x^2}$ (E) $\frac{1 + \ln x}{x^2}$

          6. If $y = \frac{\ln x}{x}$, then $\frac{dy}{dx} = $\\
(A) $\frac{1}{x}$ (B) $\frac{1}{x^2}$ (C) $\frac{\ln x - 1}{x^2}$ (D) $\frac{1 - \ln x}{x^2}$ (E) $\frac{1 + \ln x}{x^2}$

6. If y = (ln x)/(x), then (dy)/(dx) =

(A) (1)/(x) (B) (1)/(x^2) (C) (ln x - 1)/(x^2) (D) (1 - ln x)/(x^2) (E) (1 + ln x)/(x^2)

Added by Miriam J.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Breanna Ollech

Step 1

The left side of the equation is "Inx Ify" and the right side is "Uhct LtIn f 8/G CiG DIG EIG". Show more…

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Inx Ify = Uhct LtIn f 8/G CiG DIG EIG

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Question

6. If $y = \frac{\ln x}{x}$, then $\frac{dy}{dx} = $\\ (A) $\frac{1}{x}$ (B) $\frac{1}{x^2}$ (C) $\frac{\ln x - 1}{x^2}$ (D) $\frac{1 - \ln x}{x^2}$ (E) $\frac{1 + \ln x}{x^2}$

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