Inverse Trigonometric Functions: Integration 4 11. dx 1+9*2
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First, we need to simplify the denominator: 1 + 9x^2 = (3x)^2 + 1 We can use the identity: a^2 + b^2 = (a + b)(a - b) with a = 3x and b = i (the imaginary unit), to get: (3x)^2 + 1 = (3x + i)(3x - i) So, we can rewrite the denominator as: 1 + 9x^2 = (3x + Show more…
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