$$ \int_0^{2\pi} \int_0^\pi \int_0^\infty e^{-2r} r^2 \sin\phi \, dr \, d\phi \, d\theta $$
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$$ I = \left( \int_0^\infty r^2 e^{-2r} \, dr \right) \left( \int_0^\pi \sin\phi \, d\phi \right) \left( \int_0^{2\pi} 1 \, d\theta \right) $$ Show more…
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