( int_{0}^{1 / 3} frac{3+x}{(1-x)(1+3 x)} d x )
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We can write the integrand as a sum of two simpler fractions: \( \frac{3+x}{(1-x)(1+3 x)} = \frac{A}{1-x} + \frac{B}{1+3x} \) Multiplying both sides by the common denominator gives: \( 3+x = A(1+3x) + B(1-x) \) We can solve for A and B by setting x to specific Show more…
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