$f'(x) = (2 - x)(x + 3)$
Added by Michael B.
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First, let's find the critical points by setting the derivative equal to zero and solving for x: (2 - x)(x + 3) = 0 Setting each factor equal to zero, we have: 2 - x = 0 or x + 3 = 0 Solving these equations, we find: x = 2 or x = -3 These are the Show more…
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