In Problems $57-66$, write each trigonometric expression as an algebraic expression in $u$. $\sin \left(\sec ^{-1} u\right)$
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Then, $\sec(x) = u$. Recall that $\sec(x) = \frac{1}{\cos(x)}$. So, we have $\frac{1}{\cos(x)} = u$. Now, we want to find $\sin(x)$. We know that $\sin^2(x) + \cos^2(x) = 1$. Substituting $\cos(x) = \frac{1}{u}$, we get $\sin^2(x) + Show more…
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