1. Implement the function below using only one 4:1 multiplexer and only NOT gates. $f(A, B, C) = \bar{A}B + \bar{A}B\bar{C} + B\bar{C}$
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We can represent this term using a 4:1 multiplexer and NOT gates. The truth table for (1 + C) is: C | 1 + C 0 | 1 1 | 1 We can see that when C is 0, the output is 1, and when C is 1, the output is also 1. This is equivalent to a NOT gate. Show more…
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