If A= [ (Cosx -sinx) (sinx cosx)] fine A^3
Added by Juan Manuel T.
Step 1
First, we need to find A^2 by multiplying A with itself: A^2 = [ (Cosx -sinx) (sinx cosx)] [ (Cosx -sinx) (sinx cosx)] = [ (Cos^2x - Sin^2x) (2Cosx Sinx) ] [ (2Cosx Sinx) (Cos^2x - Sin^2x) ] = [ (Cos^4x - 2Cos^2x Sin^2x + Sin^4x) (4Cos^2x Sin^2x) ] = [ Show more…
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