The derivative of ln(x) is $\frac{1}{x}$.
Now, we need to evaluate sinh(ln(x)).
Recall that sinh(x) is defined as $\frac{e^x - e^{-x}}{2}$.
So, sinh(ln(x)) is $\frac{e^{\ln x} - e^{-\ln x}}{2}$.
Using the property $e^{\ln x} = x$, we get:
sinh(ln(x)) =
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