00:01
For part two, the first thing that we want to do is to sort the data.
00:05
As you can see here, i've done that ahead of time.
00:10
Reason why we want to sort the data is because we have that the median is going to be the middle point of the data set.
00:17
So we have that the rank of the median is going to be equal to one half of the sample size plus one.
00:26
Now let me just find out the sample size.
00:28
So we'd have that the rank is one is going to be 23 over two, giving a result of 11 .5, which means then that our median is going to be equal to the 11th data point plus half of the distance between the 11th and the 12th.
00:48
But i'll note that really, we could just think of this instead as it'll be midway between the 11th and 12th data points.
00:55
So it's just the average of those two values.
00:58
Now looking at the sorted data, you have that the 11th data point is five, the 12th data point is eight.
01:09
Let me just double check there.
01:10
Okay, yeah, that checks out midway between five and eight.
01:13
So that would be five plus eight over two gives a result of 6 .5 for the median.
01:23
Then for part c, to find the different core to find the lower outlier boundary and upper outlier boundary, we will first need to find the interquartile range.
01:37
Now i'm just going to quickly double check that the value that you gave for the quartiles was correct.
01:42
So the first quartile would be 75 % of the way between the fifth and sixth values.
01:48
So if your results there are incorrect, then i'll adjust but know that first one looks good...