graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $$ \begin{aligned} (x-3)^{2}+(y+1)^{2} &=9 \\ y &=x-1 \end{aligned} $$
Added by Julie N.
Step 1
To graph the first equation, we recognize that it is the equation of a circle with center (3,-1) and radius 3. We can plot the center point and then use the radius to draw the circle. To graph the second equation, we recognize that it is the equation of a line Show more…
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Graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $\begin{aligned}(x-3)^{2}+(y+1)^{2} &=9 \\ y &=x-1 \end{aligned}$
Functions and Graphs
Distance and Midpoint Formulas; Circles
graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $$\begin{aligned} (x-3)^{2}+(y+1)^{2} &=9 \\ y &=x-1\end{aligned}$$
Graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $\begin{aligned} x^{2}+y^{2} &=9 \\ x-y &=3 \end{aligned}$
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