Give a vector parametric equation for the line through the point (-3,3) that is perpendicular to the line <5-2t,-2-3t>.
Added by Kathleen C.
Step 1
We can do this by taking two points on the line and subtracting their coordinates. Let's choose (5, -2) and (-2, -5) as two points on the line: Direction vector = 〈5, -2〉 - 〈-2, -5〉 = 〈7, 3〉 Show more…
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