(g) Y = xez (h) y = axe^brtc
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For (g) Y = xez, we have: $$\frac{dY}{dx} = \frac{d(xez)}{dx}$$ Using the product rule, we get: $$\frac{dY}{dx} = e^z + x\frac{de^z}{dx}$$ Since z is a constant, the derivative of e^z with respect to x is 0. So, we have: $$\frac{dY}{dx} = \boxed{e^z}$$ For Show more…
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