To find the complex zeros, we need to solve the equation $f(x) = 0$.
$x^4 - 14x^3 + 44x^2 = 0$
$x^2(x^2 - 14x + 44) = 0$
This gives $x^2 = 0$ or $x^2 - 14x + 44 = 0$.
From $x^2 = 0$, we get $x = 0$ (with multiplicity 2).
For $x^2 - 14x + 44 = 0$, we use the
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