For the function $y = 6\ln(3x^6 + 2x^2 + 4)$, find $\frac{dy}{dx}$.
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The chain rule states that if we have a function f(g(x)), then the derivative with respect to x is f'(g(x)) * g'(x). In this case, our function is Y = 6ln(3x^6 + 2x^2 + 4), and the function inside the natural logarithm is g(x) = 3x^6 + 2x^2 + 4. So, we start by Show more…
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