Find $f \circ g \circ h$. $f(x) = 6x - 9$, $g(x) = \sin(x)$, $h(x) = x^2$ $(f \circ g \circ h)(x) = $
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The first part of the expression, "fo 1 1", means that we are taking the Fourier transform of a function with a frequency range of 1 to 1. Show moreβ¦
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