00:01
For this problem, we need to know the basic of our reciprocal function, f of x is equal to 1 over x.
00:06
So if i were to sketch this, this is going to have a vertical asymptote at x equals 0, a horizontal asymptote, also at y is equal to 0, and then it looks like this.
00:16
So for the very first one, we have the f5 over x minus 3 plus 4.
00:22
So what's going to happen is that one is going to shift to the right 3.
00:25
So we're going to go right, 1, 2, 3, and you have your vertical acetote there.
00:28
Then up four, one, two, three, four.
00:31
So we have a vertical as into it there...