Find a vector parallel to v = (3, 1) of length 2.
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The magnitude of a vector (a,b) is given by the formula: ||(a,b)|| = √(a^2 + b^2) So, the magnitude of (3,1) is: ||(3,1)|| = √(3^2 + 1^2) = √(9 + 1) = √10 Show more…
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