Question

Find vector $\mathbf{c} \times (\mathbf{a} + 3\mathbf{b})$, where $\mathbf{a}$, $\mathbf{b}$, and $\mathbf{c}$ are given below. Express your result using standard unit vectors. $\mathbf{a} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 6 & 0 & 9 \\ 0 & 1 & 0 \end{vmatrix}$, $\mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 0 & -1 & 1 \\ 8 & 1 & -1 \end{vmatrix}$, $\mathbf{c} = \mathbf{i} - \mathbf{k}$

Name: find vector mathbfc times mathbfa 3mathbfb where mathbfa mathbfb and mathbfc are given below express your result using standard unit vectors mathbfa beginvmatrix mathbfi mathbfj mathbfk 6 0 09471
Uploaded: 2019-08-05T18:54:15-08:00
Duration: 1 min 21 s
Channel: Amy Jiang
Description: find vector mathbfc times mathbfa 3mathbfb where mathbfa mathbfb and mathbfc are given below express your result using standard unit vectors mathbfa beginvmatrix mathbfi mathbfj mathbfk 6 0 09471

          Find vector $\mathbf{c} \times (\mathbf{a} + 3\mathbf{b})$, where $\mathbf{a}$, $\mathbf{b}$, and $\mathbf{c}$ are given below. Express your result using standard unit vectors.
$\mathbf{a} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 6 & 0 & 9 \\ 0 & 1 & 0 \end{vmatrix}$, $\mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 0 & -1 & 1 \\ 8 & 1 & -1 \end{vmatrix}$, $\mathbf{c} = \mathbf{i} - \mathbf{k}$

find vector mathbfc times mathbfa 3mathbfb where mathbfa mathbfb and mathbfc are given below express your result using standard unit vectors mathbfa beginvmatrix mathbfi mathbfj mathbfk 6 0 09471

Added by Denise K.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Amy Jiang

08/05/2019

Step 1

$\mathbf{a} = (0\cdot0 - 9\cdot1)\mathbf{i} - (6\cdot0 - 9\cdot0)\mathbf{j} + (6\cdot1 - 0\cdot0)\mathbf{k} = -9\mathbf{i} - 0\mathbf{j} + 6\mathbf{k} = -9\mathbf{i} + 6\mathbf{k}$ $\mathbf{b} = ((-1)\cdot(-1) - 1\cdot1)\mathbf{i} - (0\cdot(-1) - Show more…

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Find vector $\mathbf{c} \times (\mathbf{a} + 3\mathbf{b})$, where $\mathbf{a}$, $\mathbf{b}$, and $\mathbf{c}$ are given below. Express your result using standard unit vectors. $\mathbf{a} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 6 & 0 & 9 \\ 0 & 1 & 0 \end{vmatrix}$, $\mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 0 & -1 & 1 \\ 8 & 1 & -1 \end{vmatrix}$, $\mathbf{c} = \mathbf{i} - \mathbf{k}$