Question

3. find the sum of the series. (a) $3 + \frac{3}{2} + \frac{3}{4} + \frac{3}{8} + ... + \frac{3}{2^{10}}$ (b) $\sum_{n=4}^{8} \left(\frac{1}{3}\right)^n$

          3. find the sum of the series.

(a) $3 + \frac{3}{2} + \frac{3}{4} + \frac{3}{8} + ... + \frac{3}{2^{10}}$

(b) $\sum_{n=4}^{8} \left(\frac{1}{3}\right)^n$

3. find the sum of the series.

(a) 3 + (3)/(2) + (3)/(4) + (3)/(8) + ... + (3)/(2^10)

(b) ∑n=4^8((1)/(3))^n

Added by Consuelo H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Maitreya E

Step 1

Since each term is 3, we can find the number of terms by dividing the last term (210) by 3: Number of terms = 210 / 3 = 70 Now, we can use the formula for the sum of an arithmetic series: Sum = (number of terms) * (first term + last term) / 2 Show more…

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