2. Find the solution to the following initial value problem (implicit okay): $(e^y + 1)^2 e^{-y} + [(e^x + 1)^3 e^{-x}] \frac{dy}{dx} = 0$, $y(0) = 0$
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First, we can simplify the equation by multiplying both sides by e^(-x): (e^(-x))'' + (e^(-x))' = [(e^(1-x) + 1)*e^(-x)] Show more…
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