Find the Maclaurin series for the function q(x) = (2x)/(1+x^2).
Added by Rebecca R.
Step 1
Step 1: Find the derivatives of q(x) q'(x) = (2(1+x^2) - 2x(2x))/(1+x^2)^2 = 2(1-x^2)/(1+x^2)^2 q''(x) = (2(-2x)(1+x^2)^2 - 4(1-x^2)(2x)(1+x^2)(2x))/(1+x^2)^4 = 8x(3x^2-1)/(1+x^2)^4 q'''(x) = (8(3x^2-1)(1+x^2)^4 - 24x(3x^2-1)(1+x^2)^3)/(1+x^2)^6 = Show more…
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