Find the Laplace transform 4( - 5) U(t - 4)} F(s)
Added by Alfonso H.
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We have: 4(-5)U(t-4) = -20U(t-4)(1) Now, we can use the Laplace transform property for Heaviside step functions: L{U(t-a)f(t-a)} = e^{-as}F(s) In our case, a = 4 and f(t-4) = 1. So, we have: F(s) = L{-20U(t-4)(1)} = -20e^{-4s}L{1} We know that the Laplace Show more…
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