'Find the indefinite integral Jx? V3+x dx.'
Added by Marcos R.
Step 1
We can do this by multiplying both the numerator and denominator by the conjugate of the denominator, which is V3+x - V3-x. So, V3+x = (V3+x - V3-x) / (V3+x - V3-x) Now, we can rewrite the integral as: Jx? V3+x dx = Jx? (V3+x - V3-x) / (V3+x - V3-x) dx = Jx? Show more…
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