Find the direction angle of the vector \textless -6,2\textgreater .
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The magnitude of a vector is given by the formula ||v|| = sqrt(x^2 + y^2), where x and y are the components of the vector. In this case, x = -6 and y = 2. So, the magnitude of the vector is ||v|| = sqrt((-6)^2 + 2^2) = sqrt(36 + 4) = sqrt(40) = 2sqrt(10). Show more…
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