Find the derivative of the function.\ y = \frac{e^{8x}}{e^{8x} + 1}\ y' =
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The product rule states that if we have two functions u(x) and v(x), then the derivative of their product is given by: (d/dx)(u(x) * v(x)) = u'(x) * v(x) + u(x) * v'(x) In this case, u(x) = 8x and v(x) = e^(8x + 1). So, we need to find u'(x) and v'(x). Show more…
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