00:01
Okay, so for this question, we're going to solve this system of linear equations or show that the system of equations is inconsistent.
00:11
So first i'm just going to label these equations, one, two, and three.
00:18
And what we can do is try to eliminate the x variable from a couple of these equations so that if the, we cannot have two equations that are only two variables rather than three, make things a little simpler.
00:32
So the first thing we'll do is an operation equation 2 minus equation 1.
00:39
So that we'll have x minus x and we'll get 0x.
00:44
We'll also do equation 3 minus 2 times equation 1.
00:49
So that we'll have 2x minus 2 times x is 0x also.
00:53
So that will eliminate the x variable from both the second and third equations.
00:59
We'll do the equation to operation first.
01:02
So x minus x is 0.
01:04
So we'll cross that out as 0.
01:09
Then we have 2y minus y, which is just y.
01:13
Then we have negative 3 z minus negative z is negative 2 z.
01:20
Then we have negative 3 minus 0 is negative 3.
01:25
And this is the new equation 2.
01:29
So the next operation we get 2x minus 2 times x is 0x.
01:35
So we'll cross that out and it's 0.
01:37
Then we have 3y minus 2 times y is just y.
01:45
Then we have negative 4 z minus 2 times negative z is negative 2 then we have negative 3 minus 0 or minus 2 times 0 is negative 3.
02:01
Now you may notice that these two equations are actually exactly the same...